{"id":16052,"date":"2023-06-07T05:15:32","date_gmt":"2023-06-06T21:15:32","guid":{"rendered":"https:\/\/www.study-together.com\/edu\/?p=16052"},"modified":"2023-06-07T05:48:03","modified_gmt":"2023-06-06T21:48:03","slug":"dse-m1-poisson-distribution-problem-average-number-of-breakdowns","status":"publish","type":"post","link":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/","title":{"rendered":"DSE M1 Poisson Distribution Problem – Average Number of Breakdowns."},"content":{"rendered":"\t\t
\n\t\t\t\t\t\t
\n\t\t\t\t\t\t
\n\t\t\t\t\t
\n\t\t\t
\n\t\t\t\t\t\t
\n\t\t\t\t
\n\t\t\t\t\t\t\t\t\t

Let X be the number of breakdowns of the photocopier in a year. Since the distribution of X follows a Poisson distribution, the probability of having exactly \\(\\lambda\\) breakdowns in a year is given by:<\/p>

\\(P(X = x) = \\dfrac{ \\lambda^{x}}{x!} e^{-\\lambda}\\)<\/p>

a) As the probabilities for the photocopier to have exactly 2 repairs and exactly 3 repairs in a year are the same.<\/p>

\\(\\begin{align}
\\dfrac{\\lambda^{2}}{2!} e^{-\\lambda} &= \\dfrac{ \\lambda^{3}}{3!} e^{-\\lambda} \\\\
\\dfrac{ \\lambda^{2}}{2!} &= \\dfrac{ \\lambda^{3}}{3!}\u00a0 \\\\
\\lambda &= 1.5 \\\\
\\end{align}\\)<\/p>

b i) Expected repair charge in a year if paln II is adopted<\/p>

\\(\\begin{align}
&= P(X = 0) \\times 0 + P(X = 1) \\times 1000 + P(X = 2) \\times 1800 + P(X = 3) \\times 2600\u00a0 \\\\
&= 0 + 1000 \\times \\dfrac{ 1.5^{1}}{1!} e^{-1.5} + 1800 \\times \\dfrac{ 1.5^{2}}{2!} e^{-1.5} + 2600 \\times \\dfrac{ 1.5^{3}}{3!} e^{-1.5} \\\\
&= 0.3347 \\times 1000 + 0.2510 \\times 1800 + 0.1255 \\times\u00a0 2600\\\\
&= $1112.8
\\end{align}\\)<\/p>

b ii) As the expected repair charge in a year for plan II is less than that for plan I, plan II should be chosen to minimize the repair charge.<\/p>

\u554f\u984c\u4f86\u6e90: \u4e2d\u5b78\u6578\u5b78\u529f\u8ab2\u4ea4\u6d41\u5340<\/a><\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<\/div>\n\t\t","protected":false},"excerpt":{"rendered":"

Let X be the number of breakdowns of the photocopier in […]<\/p>\n","protected":false},"author":1,"featured_media":16053,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"ocean_post_layout":"","ocean_both_sidebars_style":"","ocean_both_sidebars_content_width":0,"ocean_both_sidebars_sidebars_width":0,"ocean_sidebar":"0","ocean_second_sidebar":"0","ocean_disable_margins":"enable","ocean_add_body_class":"","ocean_shortcode_before_top_bar":"","ocean_shortcode_after_top_bar":"","ocean_shortcode_before_header":"","ocean_shortcode_after_header":"","ocean_has_shortcode":"","ocean_shortcode_after_title":"","ocean_shortcode_before_footer_widgets":"","ocean_shortcode_after_footer_widgets":"","ocean_shortcode_before_footer_bottom":"","ocean_shortcode_after_footer_bottom":"","ocean_display_top_bar":"default","ocean_display_header":"default","ocean_header_style":"","ocean_center_header_left_menu":"0","ocean_custom_header_template":"0","ocean_custom_logo":0,"ocean_custom_retina_logo":0,"ocean_custom_logo_max_width":0,"ocean_custom_logo_tablet_max_width":0,"ocean_custom_logo_mobile_max_width":0,"ocean_custom_logo_max_height":0,"ocean_custom_logo_tablet_max_height":0,"ocean_custom_logo_mobile_max_height":0,"ocean_header_custom_menu":"0","ocean_menu_typo_font_family":"0","ocean_menu_typo_font_subset":"","ocean_menu_typo_font_size":0,"ocean_menu_typo_font_size_tablet":0,"ocean_menu_typo_font_size_mobile":0,"ocean_menu_typo_font_size_unit":"px","ocean_menu_typo_font_weight":"","ocean_menu_typo_font_weight_tablet":"","ocean_menu_typo_font_weight_mobile":"","ocean_menu_typo_transform":"","ocean_menu_typo_transform_tablet":"","ocean_menu_typo_transform_mobile":"","ocean_menu_typo_line_height":0,"ocean_menu_typo_line_height_tablet":0,"ocean_menu_typo_line_height_mobile":0,"ocean_menu_typo_line_height_unit":"","ocean_menu_typo_spacing":0,"ocean_menu_typo_spacing_tablet":0,"ocean_menu_typo_spacing_mobile":0,"ocean_menu_typo_spacing_unit":"","ocean_menu_link_color":"","ocean_menu_link_color_hover":"","ocean_menu_link_color_active":"","ocean_menu_link_background":"","ocean_menu_link_hover_background":"","ocean_menu_link_active_background":"","ocean_menu_social_links_bg":"","ocean_menu_social_hover_links_bg":"","ocean_menu_social_links_color":"","ocean_menu_social_hover_links_color":"","ocean_disable_title":"default","ocean_disable_heading":"default","ocean_post_title":"","ocean_post_subheading":"","ocean_post_title_style":"","ocean_post_title_background_color":"","ocean_post_title_background":0,"ocean_post_title_bg_image_position":"","ocean_post_title_bg_image_attachment":"","ocean_post_title_bg_image_repeat":"","ocean_post_title_bg_image_size":"","ocean_post_title_height":0,"ocean_post_title_bg_overlay":0.5,"ocean_post_title_bg_overlay_color":"","ocean_disable_breadcrumbs":"default","ocean_breadcrumbs_color":"","ocean_breadcrumbs_separator_color":"","ocean_breadcrumbs_links_color":"","ocean_breadcrumbs_links_hover_color":"","ocean_display_footer_widgets":"default","ocean_display_footer_bottom":"default","ocean_custom_footer_template":"0","ocean_post_oembed":"","ocean_post_self_hosted_media":"","ocean_post_video_embed":"","ocean_link_format":"","ocean_link_format_target":"self","ocean_quote_format":"","ocean_quote_format_link":"post","ocean_gallery_link_images":"off","ocean_gallery_id":[],"footnotes":""},"categories":[34],"tags":[22,26],"class_list":["post-16052","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-hkdse-maths-m1","tag-dse-","tag-26","entry","has-media"],"yoast_head":"\nDSE M1 Poisson Distribution Problem - Average Number of Breakdowns. » \u9f4a\u9f4a\u6eab<\/title>\n<meta name=\"description\" content=\"The number of breakdowns of a photocopier in a year follows a Poisson distribution, and the average is k breakdowns per year. It is known that the probabilities for the photocopier to have exactly 2 repairs and exactly 3 repairs in a year are the same. Find k.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/\" \/>\n<meta property=\"og:locale\" content=\"zh_TW\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"DSE M1 Poisson Distribution Problem - Average Number of Breakdowns. » \u9f4a\u9f4a\u6eab\" \/>\n<meta property=\"og:description\" content=\"The number of breakdowns of a photocopier in a year follows a Poisson distribution, and the average is k breakdowns per year. It is known that the probabilities for the photocopier to have exactly 2 repairs and exactly 3 repairs in a year are the same. Find k.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/\" \/>\n<meta property=\"og:site_name\" content=\"\u9f4a\u9f4a\u6eab\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/-100355795002387\" \/>\n<meta property=\"article:published_time\" content=\"2023-06-06T21:15:32+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-06-06T21:48:03+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.study-together.com\/edu\/wp-content\/uploads\/2023\/06\/m1_poisson_problem_20230607.webp\" \/>\n\t<meta property=\"og:image:width\" content=\"1600\" \/>\n\t<meta property=\"og:image:height\" content=\"775\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/webp\" \/>\n<meta name=\"author\" content=\"WingSir\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\\\/\\\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/#article\",\"isPartOf\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/\"},\"author\":{\"name\":\"WingSir\",\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/#\\\/schema\\\/person\\\/6e323b117b2819082cc3839c064dcb48\"},\"headline\":\"DSE M1 Poisson Distribution Problem – Average Number of Breakdowns.\",\"datePublished\":\"2023-06-06T21:15:32+00:00\",\"dateModified\":\"2023-06-06T21:48:03+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/\"},\"wordCount\":172,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/#organization\"},\"image\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/#primaryimage\"},\"thumbnailUrl\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/wp-content\\\/uploads\\\/2023\\\/06\\\/m1_poisson_problem_20230607.webp\",\"keywords\":[\"DSE \u6578\u5b78\",\"\u554f\u984c\u89e3\u7b54\"],\"articleSection\":[\"HKDSE Maths M1\"],\"inLanguage\":\"zh-TW\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/\",\"url\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/\",\"name\":\"DSE M1 Poisson Distribution Problem - Average Number of Breakdowns. » \u9f4a\u9f4a\u6eab\",\"isPartOf\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/#primaryimage\"},\"image\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/#primaryimage\"},\"thumbnailUrl\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/wp-content\\\/uploads\\\/2023\\\/06\\\/m1_poisson_problem_20230607.webp\",\"datePublished\":\"2023-06-06T21:15:32+00:00\",\"dateModified\":\"2023-06-06T21:48:03+00:00\",\"description\":\"The number of breakdowns of a photocopier in a year follows a Poisson distribution, and the average is k breakdowns per year. It is known that the probabilities for the photocopier to have exactly 2 repairs and exactly 3 repairs in a year are the same. Find k.\",\"breadcrumb\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/#breadcrumb\"},\"inLanguage\":\"zh-TW\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/\"]}]},{\"@type\":\"ImageObject\",\"inLanguage\":\"zh-TW\",\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/#primaryimage\",\"url\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/wp-content\\\/uploads\\\/2023\\\/06\\\/m1_poisson_problem_20230607.webp\",\"contentUrl\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/wp-content\\\/uploads\\\/2023\\\/06\\\/m1_poisson_problem_20230607.webp\",\"width\":1600,\"height\":775},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/2023\\\/06\\\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\\\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"DSE M1 Poisson Distribution Problem – Average Number of Breakdowns.\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/#website\",\"url\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/\",\"name\":\"\u9f4a\u9f4a\u6eab\",\"description\":\"\u4e2d\u5b78\u53ca\u5c0f\u5b78\u8ab2\u7a0b - \u9f4a\u9f4a\u5b78!\u9f4a\u9f4a\u6eab!\",\"publisher\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/?s={search_term_string}\"},\"query-input\":{\"@type\":\"PropertyValueSpecification\",\"valueRequired\":true,\"valueName\":\"search_term_string\"}}],\"inLanguage\":\"zh-TW\"},{\"@type\":\"Organization\",\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/#organization\",\"name\":\"Study2Gather\",\"url\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"zh-TW\",\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/#\\\/schema\\\/logo\\\/image\\\/\",\"url\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/wp-content\\\/uploads\\\/2020\\\/06\\\/logo.png\",\"contentUrl\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/wp-content\\\/uploads\\\/2020\\\/06\\\/logo.png\",\"width\":250,\"height\":55,\"caption\":\"Study2Gather\"},\"image\":{\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/#\\\/schema\\\/logo\\\/image\\\/\"},\"sameAs\":[\"https:\\\/\\\/www.facebook.com\\\/-100355795002387\"]},{\"@type\":\"Person\",\"@id\":\"https:\\\/\\\/www.study-together.com\\\/edu\\\/#\\\/schema\\\/person\\\/6e323b117b2819082cc3839c064dcb48\",\"name\":\"WingSir\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"zh-TW\",\"@id\":\"https:\\\/\\\/secure.gravatar.com\\\/avatar\\\/bafa8324750ba54a2bca0ed09eded533e2b1152a5718e91ac1b1e73e3bdebee9?s=96&d=mm&r=g\",\"url\":\"https:\\\/\\\/secure.gravatar.com\\\/avatar\\\/bafa8324750ba54a2bca0ed09eded533e2b1152a5718e91ac1b1e73e3bdebee9?s=96&d=mm&r=g\",\"contentUrl\":\"https:\\\/\\\/secure.gravatar.com\\\/avatar\\\/bafa8324750ba54a2bca0ed09eded533e2b1152a5718e91ac1b1e73e3bdebee9?s=96&d=mm&r=g\",\"caption\":\"WingSir\"}}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"DSE M1 Poisson Distribution Problem - Average Number of Breakdowns. » \u9f4a\u9f4a\u6eab","description":"The number of breakdowns of a photocopier in a year follows a Poisson distribution, and the average is k breakdowns per year. It is known that the probabilities for the photocopier to have exactly 2 repairs and exactly 3 repairs in a year are the same. Find k.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/","og_locale":"zh_TW","og_type":"article","og_title":"DSE M1 Poisson Distribution Problem - Average Number of Breakdowns. » \u9f4a\u9f4a\u6eab","og_description":"The number of breakdowns of a photocopier in a year follows a Poisson distribution, and the average is k breakdowns per year. It is known that the probabilities for the photocopier to have exactly 2 repairs and exactly 3 repairs in a year are the same. Find k.","og_url":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/","og_site_name":"\u9f4a\u9f4a\u6eab","article_publisher":"https:\/\/www.facebook.com\/-100355795002387","article_published_time":"2023-06-06T21:15:32+00:00","article_modified_time":"2023-06-06T21:48:03+00:00","og_image":[{"width":1600,"height":775,"url":"https:\/\/www.study-together.com\/edu\/wp-content\/uploads\/2023\/06\/m1_poisson_problem_20230607.webp","type":"image\/webp"}],"author":"WingSir","twitter_card":"summary_large_image","schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/#article","isPartOf":{"@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/"},"author":{"name":"WingSir","@id":"https:\/\/www.study-together.com\/edu\/#\/schema\/person\/6e323b117b2819082cc3839c064dcb48"},"headline":"DSE M1 Poisson Distribution Problem – Average Number of Breakdowns.","datePublished":"2023-06-06T21:15:32+00:00","dateModified":"2023-06-06T21:48:03+00:00","mainEntityOfPage":{"@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/"},"wordCount":172,"commentCount":0,"publisher":{"@id":"https:\/\/www.study-together.com\/edu\/#organization"},"image":{"@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/#primaryimage"},"thumbnailUrl":"https:\/\/www.study-together.com\/edu\/wp-content\/uploads\/2023\/06\/m1_poisson_problem_20230607.webp","keywords":["DSE \u6578\u5b78","\u554f\u984c\u89e3\u7b54"],"articleSection":["HKDSE Maths M1"],"inLanguage":"zh-TW","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/","url":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/","name":"DSE M1 Poisson Distribution Problem - Average Number of Breakdowns. » \u9f4a\u9f4a\u6eab","isPartOf":{"@id":"https:\/\/www.study-together.com\/edu\/#website"},"primaryImageOfPage":{"@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/#primaryimage"},"image":{"@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/#primaryimage"},"thumbnailUrl":"https:\/\/www.study-together.com\/edu\/wp-content\/uploads\/2023\/06\/m1_poisson_problem_20230607.webp","datePublished":"2023-06-06T21:15:32+00:00","dateModified":"2023-06-06T21:48:03+00:00","description":"The number of breakdowns of a photocopier in a year follows a Poisson distribution, and the average is k breakdowns per year. It is known that the probabilities for the photocopier to have exactly 2 repairs and exactly 3 repairs in a year are the same. Find k.","breadcrumb":{"@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/#breadcrumb"},"inLanguage":"zh-TW","potentialAction":[{"@type":"ReadAction","target":["https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/"]}]},{"@type":"ImageObject","inLanguage":"zh-TW","@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/#primaryimage","url":"https:\/\/www.study-together.com\/edu\/wp-content\/uploads\/2023\/06\/m1_poisson_problem_20230607.webp","contentUrl":"https:\/\/www.study-together.com\/edu\/wp-content\/uploads\/2023\/06\/m1_poisson_problem_20230607.webp","width":1600,"height":775},{"@type":"BreadcrumbList","@id":"https:\/\/www.study-together.com\/edu\/2023\/06\/dse-m1-poisson-distribution-problem-average-number-of-breakdowns\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/www.study-together.com\/edu\/"},{"@type":"ListItem","position":2,"name":"DSE M1 Poisson Distribution Problem – Average Number of Breakdowns."}]},{"@type":"WebSite","@id":"https:\/\/www.study-together.com\/edu\/#website","url":"https:\/\/www.study-together.com\/edu\/","name":"\u9f4a\u9f4a\u6eab","description":"\u4e2d\u5b78\u53ca\u5c0f\u5b78\u8ab2\u7a0b - \u9f4a\u9f4a\u5b78!\u9f4a\u9f4a\u6eab!","publisher":{"@id":"https:\/\/www.study-together.com\/edu\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/www.study-together.com\/edu\/?s={search_term_string}"},"query-input":{"@type":"PropertyValueSpecification","valueRequired":true,"valueName":"search_term_string"}}],"inLanguage":"zh-TW"},{"@type":"Organization","@id":"https:\/\/www.study-together.com\/edu\/#organization","name":"Study2Gather","url":"https:\/\/www.study-together.com\/edu\/","logo":{"@type":"ImageObject","inLanguage":"zh-TW","@id":"https:\/\/www.study-together.com\/edu\/#\/schema\/logo\/image\/","url":"https:\/\/www.study-together.com\/edu\/wp-content\/uploads\/2020\/06\/logo.png","contentUrl":"https:\/\/www.study-together.com\/edu\/wp-content\/uploads\/2020\/06\/logo.png","width":250,"height":55,"caption":"Study2Gather"},"image":{"@id":"https:\/\/www.study-together.com\/edu\/#\/schema\/logo\/image\/"},"sameAs":["https:\/\/www.facebook.com\/-100355795002387"]},{"@type":"Person","@id":"https:\/\/www.study-together.com\/edu\/#\/schema\/person\/6e323b117b2819082cc3839c064dcb48","name":"WingSir","image":{"@type":"ImageObject","inLanguage":"zh-TW","@id":"https:\/\/secure.gravatar.com\/avatar\/bafa8324750ba54a2bca0ed09eded533e2b1152a5718e91ac1b1e73e3bdebee9?s=96&d=mm&r=g","url":"https:\/\/secure.gravatar.com\/avatar\/bafa8324750ba54a2bca0ed09eded533e2b1152a5718e91ac1b1e73e3bdebee9?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/bafa8324750ba54a2bca0ed09eded533e2b1152a5718e91ac1b1e73e3bdebee9?s=96&d=mm&r=g","caption":"WingSir"}}]}},"_links":{"self":[{"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/posts\/16052","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/comments?post=16052"}],"version-history":[{"count":16,"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/posts\/16052\/revisions"}],"predecessor-version":[{"id":16094,"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/posts\/16052\/revisions\/16094"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/media\/16053"}],"wp:attachment":[{"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/media?parent=16052"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/categories?post=16052"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.study-together.com\/edu\/wp-json\/wp\/v2\/tags?post=16052"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}